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We say that a linear transformation is onto W if the range of L is equal to W Example Let L be the linear transformation from R 2 to R 3 defined by L(v) = Avwith A Find a basis for Ker(L) B Determine of L is 11 C Find a basis for the range of L D Determine if L is onto Solution The Ker(L) is the same as the null space of the matrix AWe have. Var ha,ia,ja,ma,sa,na,ta,ya,Ja;_ea=function(a){return function(){return _daaapply(this,arguments. @ ԂƗ΂Ɉ͂܂ꂽ X B h C u ̓r Ȃǔ ꂽ ̂ ăz b ƈꑧ I ᖡ h b v I R q Ƃ ύ 񂾎 Ɛ ̃X C c ͑ l C B y H ̓X p Q e B A J A n o O ȂǃT _ E R q t ̂ ȃZ b g A ؂ p ̃X y V ܂ g X g ͈ x H ׂ n } b Ⴂ ܂ I.

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V xx = 0 Therefore v(x) = c 1 c 2x, for some constants c 1 and c 2 v(x) must also satisfy the boundary conditions v(0) = 10 and v(50) = 40 so 10 = v(0) = c 1 and 40 = v(50) = c 1 50c 2 = 1050c 2 Thus c 2 = 3 5 and v(x) = 10 3 5 x 4 u x(0,t) = 0, u(L,t) = T The steadystate solution v(x) must satisfy the differential equation with v t. 14 N8 4 ^ 싅 c J n C ^ N 1 2 3 4 5 6 7 8 R d 0 0 0 0 0 0 ̊ۃ b h T Y 11 3 3 0 X 17. 3 Signals and Systems Part II Solutions to Recommended Problems S31 (a) xn= 8n 8 n 3 n 0 1 2 3 Figure S311 (b) xn = unun 5 0041T 0 1 2 3 4 5.